How do i solve the 6th hidden case in Go switch lesson

Question

Go course , the switch lesson requires i solve a code coach problem, i did and my code worked in all but one hidden case ,
Here's the code:
package main

import "fmt"

func main() {
var f int
fmt.Scanln(&f)

switch {
case f < 20: fmt.Println("Infrasound")
case f > 20000: fmt.Println("Ultrasound")
default:
if 20 <= f && f <= 20000 {
fmt.Println("Audible")
} else {
fmt.Println("Wrong input")
}
}
}

Answer 1

Ok so the problem was that "Wrong Input" is not the same as "Wrong input" ... Kill me

Answer 2

**🇦🇪|🇦🇪**

package main

import "fmt"

func main() {
var f int
fmt.Scanln(&f)
//your code goes here
switch
{
case f<0:
fmt.Println("Wrong Input")
case f<20:
fmt.Println("Infrasound")
case f>20000:
fmt.Println("Ultrasound")
default:
fmt.Println("Audible")
}
}

Answer 3

if f = -34
the first case return true >>>Infrasound
so you should include f >0
so the code will output Wrong Input when f < 0

Answer 4

switch {
case f < 0:
fmt.Println("Wrong Input")
case f < 20:
fmt.Println ("Infrasound")
case f > 20000:
fmt.Println ("Ultrasound")
case f > 20 && f <= 20000:
fmt.Println("Audible") }