Lambda function python: print((lambda x: print(x))(5))

Question

print((lambda x: print(x))(5))
Why is this outputting “5” and “None”?
Can somebody help?
Thankyou.

Answer 1

Rajat Kumar ,

the inner part of the expression mentioned by you is:

(lambda x: print(x))(5)

the lambda gets an argument (5), which will be output by the print() function that is inside the lambda. this execution does not have any *explicite* value that is returned. so *none* is used as return value.

the mentioned lambda is used as an argument in an other (outer) print() statement, which just outputs the *none value*. remove the outer print() statement to get only the valus of 5.

normally lambdas are not used to do outputs, but they *return* values. better to use the outer print() statement and remove the inner ones.

sample: print((lambda x: x*2)(5))

this lambda gets 5 as argument, multiplies it by 2. this then used as argument for the print() statement. result is 10.