#include <stdio.h> int main() { int x=7%4*3/2; printf("%d \n",x); return 0;}

Question

Can anyone tell me why it's ans is 1 unless in coding it gives ans 4.

Answer 1

ANKIT RAJ
In this program the expression `7%4*3/2` is evaluated according to the operator precedence rules.
#This operator `%` has higher precedence

#than the multiplication operator `*`

# and then division operator `/`.

So given expression is: `(7%4)*3/2`

First, `7%4`
which gives the remainder of 7 divided by 4, which is 3.

Note that:-
The `%` operator is called the modulus operator. It calculates the remainder when one number is divided by another.
hence,7%4=3

Second, `(7%4)*3`=(3)*3
which is 3 multiplied by 3, resulting in 9.

Finally, `9/2`
which gives the integer division of 9 by 2, resulting in 4.

Note that:-
The `/` operator is used for division.
It performs division between two numbers and returns the quotient..

hence, the answer is 4, not 1.