I’m working on Izzy the Iguana code coach challenge. My code work for all but 1 test case. What am I missing?!??

Question

Unfortunately the test case was locked so I can’t even see what was inputted but here is my code:

https://sololearn.com/compiler-playground/ccD7h194LPb4/?ref=app

Answer 1

Josh Rhodes
A hint:
You iterate in for loop over the items of the list but each time don‘t check the item only whole list.

Answer 2

Josh Rhodes ,
yes this was intended solution. Here inclusive a few improvements:

snacks = input().split()
pts = 0
for i in snacks:
if i == "Lettuce":
pts = pts + 5
elif i == "Carrot":
pts = pts + 4
elif i == "Mango":
pts = pts + 9
else:
continue
if pts >= 10:
print("Come on Down!")
else:
print("Time to wait")

Answer 3

Josh Rhodes ,

your code is built like this:

snacks = input().split()
pts = 0
for i in snacks:
if "Lettuce" in snacks:
pts = pts + 5
...

one test fails.

as JaScript already mentioned, the iteration you use should be modified for all cases. we can do it like:

snacks = input().split()
pts = 0
for i in snacks:
if i == 'Lettuce':
pts = pts + 5
...

Answer 4

Rik Wittkopp ,

the code can be seen on windows pc but not on mobile devices. it is not dependend on having pro.

Answer 5

Can you show your attempt

The link to the challenge is not connecting, pro subscription required.

Also, what are the requirements of the challenge

Answer 6

Thanks for all the tips and hints guys but I finally solved it with an easy fix.

Heres the new code:

https://code.sololearn.com/ccD7h194LPb4/?ref=app

Answer 7

Josh Rhodes
I found the challenge, so if you show your attempt, I can review and assist

Answer 8

Josh Rhodes, post your code with this description.

https://code.sololearn.com/Wek0V1MyIR2r/?ref=app

Answer 9

Wong Hei Ming I figured out how to post the correct url. I have to add “code.” before “sololearn” and then delete “compiler-playground”.

https://code.sololearn.com/ccD7h194LPb4/?ref=app

Answer 10

Josh Rhodes, congratulation you pass this exercise.
Below is the code to use a dictionary, along with comments to help you learn.

# Lettuce is worth 5, Carrot is worth 4, Mango is worth 9, and Cheeseburger is worth 0
foods = {"Lettuce": 5,
"Carrot": 4,
"Mango" : 9,
"Cheeseburge": 0}

snacks = input()
snacks = snacks.split()

points = 0

'''
use the dictionay get() method
the first argument is the key
and second argument is the return value if the key is not found
'''
for snack in snacks:
point = foods.get(snack, 0)
points += point

'''
For the last 2 lines you can write like this:
points += foods.get(snack, 0)
However, it takes some time to understand the code
It is bette to make the code simple and easier to debug with
'''

if points >= 10:
print("Come on Down!")
else:
print("Time to wait")

Answer 11

If you already reach Collection Type in the intermediate course, you will find using a dictionary is a better choice in this challenge.

Answer 12

Helo guys am kindly requesting anyone who can help me code

Answer 13

My first idea was to use a dictionary but I couldnt figure out how to call all the values and add them together.

So I solved it the only other way I could think of.