Why it is not work? Cpp

Question

Were is the proplem in this code ?

https://code.sololearn.com/c9a3KDgJW2sY/?ref=app

Answer 1

Y-Kh first let's not blame python for a c++ code and look at the "forloop" as Lothar mentioned x won't get to 1000 until x reaches 1000 but you forgot curl brackets { after the for conditional iteration

for(x=1;x<=1000;x++){

// then you are asking to print "cout" after each iteration... I added the "\n"; to address x on each line until you reach 1000

cout<<x<<"\n";

// We need a closing curl bracket for the "forloop" to properly loop
}

// Then our return 0; with a closing curl bracket for our main

return 0;
}

Answer 2

Y-Kh ,

> the condition in the loop can not get true, so no output is given.

probably you mean:

...
for(x=1;x<=1000;x++)
^^^

> an other optimization could be to add a space after each number in output:

...
cout<<x<<" ";
^^^^^

Answer 3

Rizwan ali your copy and paste web code has absolutely nothing to do with this question, as it is spam.

Answer 4

Bob_Li if they only use it this was
for(x=1;x==1000;x++){
}
cout << x ;

The quick answer is 1

Answer 5

The middle value in the for loop is the condition that should be TRUE while running. The for loop stops when it is False.

it is not the target condition.

Think of it as a form of while-loop.

x==1000 is false (because x=1, and 1==1000 is false).
That's why there is no output.

x<=1000 is true (because x=1 and 1<=1000 is true)
This will make the loop run and increment x until the condition is false.
Then you output 123456....1000

The loop stops when the middle condition is false.

Answer 6

https://code.sololearn.com/cNvgG8VTIW3E/?ref=app