The code doesn't work

Question

The code is supposed to count the number of vowels in a string and it doesn't work?

x = input("Enter a string:")
z = 0
y =0
for i in x:
if i== 'a' or 'A':
y +=1
elif i == 'e' or 'E':
y +=1
elif i == 'i' or 'I':
y +=1
elif i == 'o' or 'O':
y +=1
elif i== 'u' or 'U':
y +=1
else:
z = 0
print("the output:", y)

Answer 1

You are using `i == 'a' or 'A'`.
It's corrected form is `i == 'a' or i == 'A'` as I do below.
https://sololearn.com/compiler-playground/cgpyxr4Y3HpY/?ref=app

Answer 2

It should be
if i == 'a' or i == 'A'.

An alternative is
if i in 'aA'

or much simpler
if i in 'aeiouAEIOU'.

Answer 3

Infernyx ,

> your code defines / initialize a variable `z` with 0.

> in the `else` clause the value of 0 will be assigned to variable `z`.

> but this varisble is never used.

Answer 4

Or turn the i to lower case and get rid of all or statements

for i in x:
i = i.lower()
if(i in "aeiou"):
y += 1

Answer 5

Thank you for helping me people