Can somebody please explain how the output is 02?

Question

int x=3;
if(x=2)
cout<<"0";
else
cout<<"1";
cout<<x;

Answer 1

well in if statement you have = (assigment) so x is becoming 2, and it is true, so you have cout 0 and after that printing new value of x

Answer 2

yea. use x==2 instead

Answer 3

= is assignment operator or relational

u have to use ==

Answer 4

Use == (syntax variable == variable and also note that numbers count as variables)
instead of =, which assigns variables to variables (relational).\
This is what you should want:
int x=3;
if(x==2)
cout<<"0";
else
cout<<"1";

cout<<x;

In the original code it sets x to 2, then in the first if statement it becomes true, so it outputs 0. The else statement becomes false. Then it outputs x (which is 2).
Output: 02 (in original code).

Answer 5

Tips:You got mucked up with = and ==