I write a python code for "Take a phrase and replace any instances of an integer from 0-10 and replace it with the English word.

Question

```
def replace_numbers(phrase):
numbers = {
'0': 'zero', '1': 'one', '2': 'two', '3': 'three', '4': 'four',
'5': 'five', '6': 'six', '7': 'seven', '8': 'eight', '9': 'nine', '10': 'ten'
}
for key, value in numbers.items():
phrase = phrase.replace(key, value)
return phrase

phrase = input()
print(replace_numbers(phrase))
```

My code is perfect and solves that problem but it is right with 5 conditions not all six, Why?

Answer 1

First replace 10, then the single digits.

Answer 2

Oh,thanks Lothar

Answer 3

When the input is "10", your code will translate it to "onezero".

Answer 4

https://sololearn.com/compiler-playground/cGCljT7hMzZI/?ref=app

Answer 5

Manish Kumar ,

a different approach that solves the issue of replacing the number 10 (and some others):

read the input-string, and split it into chunks by using the spaces as a separator. then iterate over the resulting list of the mentioned step and do the replacement.

Answer 6

Yes, you are right, how can I solve this problem?

Answer 7

Thank you!

Answer 8

Daniel ,

the sample code that you have posted creates an error in the last line (print(…)). the variable ‘f‘ is not declared.

Answer 9

A variation on Daniel's code that still applies Lothar's approach.
1 - create list instead of dictionary of the string version of numbers.
2 - when looping over the list of strings created by splitting phrase, check if string is just numerals with isnumeric()
3 - convert to int and if 10 or less, use as index for list to get string version of numbers.
4 - can overwrite the entry in phrase list instead of appending to new list

https://sololearn.com/compiler-playground/cJmSYLmxU3TM/?ref=app