What does f*=i; really do in this code

Question

#include <iostream>

int main()
{
int f=1, i=2;
while(++i<5) {
f*=i; // what is this suposed to do ?
}
std::cout<<f<<std::endl;
return 0;
}

Answer 1

f *= i;

is similar to

f = f * i;

It assigns the product of f and i to f for each loop.

Answer 2

Just leave it for future reference. :>

Answer 3

Thank you i wasnt sure if that was the case for multiplications also.
Should i delete a question after im answered or leave it there ?

Answer 4

it simply multiplies the variables f & i and stores the result in variable f.
f*=i means f=f*i

Answer 5

This was helpful.

also, I used http://cpp.sh/ to run the following. Interesting exponential jumps with this loop/function/expression:

/ Example program
using namespace std;
#include <fstream>
#include <iostream>
#include <string>

int main()
{
int f=1, i=2;
while(++i<12) {
f*=i;
cout<<f << endl;
}

}

Output:

3
12
60
360
2520
20160
181440
1814400
19958400