+ 1
This is a SoloLearn Question, is my answer wrong?
what is the out put of this code? int n = 5; int m = 7; int z = 6; if (++n < m & z==n++) Console.Write(m); else Console.Write(n); My Answer: 7
10 Réponses
+ 11
yeah thank you @jeth
+ 9
++n and n++
do you know the difference . you are wrong there in prefix and suffix.
+ 9
There is a big difference between postfix and prefix versions of ++ .
In the prefix version (i.e., ++i ), the value of i is incremented, and the value of the expression is the new value of i . <---. This one, the value is new.
In the postfix version (i.e., i++ ), the value of i is incremented, but the value of the expression is the original value of i .
Let's analyze the following code line by line:
int i = 10 ; // (1)
int j = ++i; // (2)
int k = i++; // (3)
1. i is set to 10 (easy).
2. Two things on this line:
i is incremented to 11 .
The new value of i is copied into j. So j now equals 11 .
3. Two things on this line as well:
i is incremented to 12 .
The original value of i (which is
11 ) is copied into k . So k now equals 11 .
So after running the code, i will be 12 but both j and k will be 11.
The same stuff holds for postfix and prefix versions of -- .
@copyright of stackoverflow
+ 1
Your answer is right.
0
but, solo says I'm wrong.
0
Solo says incorrect. You can test this code in IDE and see that it outputs 7.
0
yeah I did that.
0
++n increments value BEFORE comparing while n++ do it AFTER comparing.
0
So did you read that and understood why answer is 7? Here is playground test btw:
https://code.sololearn.com/ceGjD6IRqhLs/?ref=app
0
yeah thanks @jeth