+ 2
Can anyone explain the logic? I've tried many times
How is the output 52? public class Program { public static void main(String[] args) { int x=0,y=0; for(int j=1;j<5;j++){ if(++x>2&&++y>1) { x++; } } System.out.print(x+""+y); } }
4 Réponses
+ 8
ok well the first thing is to remember how java evaluates multiple conditions.
if (++x > 2 && ++y > 1)
if ++x > 2 is false, then java wont evaluate the other side, because if one side is false, then false && anything will always be false, hence the right side isnt evaluated (++y isnt incremented)
so with that in mind, if ++x > 2 is true, it will evaluate ++y > 1 and if that is also true, then the if branch is executed. now lets go through it:
j x y
------------
1 1 1
2 2 0
3 3 1
4 4 2
5
the inside of the if branch is executed when j = 4 because then both conditions of the if statement are true, so finally x is incremented from 4 to 5
so x is 5 and y is 2 if i did it correctly
+ 6
@Edward: Nice Answer!
+ 4
thanks @jay. and no problem @prathamesh. i also didnt know that when i first started learning java.
same goes for ||
if (x > 2 || y > 7)
if x> 2 is true, then the body is executed because
true || anything else is always true.
only evaluates the right side if x > 2 is false
+ 3
Didn't know java evaluated conditions like this. Thanks for the explanation. You are awesome!