Making 6 different random Numbers.

Question

I'm not that good at coding right now, i am trying to improve and learn. ATM i was trying to write a code that randomly picks 6 non-repeating numbers, but i fail at it. what should i do?

<code>

import random

a = random.randint(1, 100)
b = random.randint(1, 100)
c = random.randint(1, 100)
x = random.randint(1, 100)
y = random.randint(1, 100)
z = random.randint(1, 100)

outa = b, c, x, y, z
outb = a, c, x, y, z
outc = a, b, x, y, z
outx = a, b, c, y, z
outy = a, b, c, x, z
outz = a, b, c, x, y

all = a, b, c, x, y, z

while a in outa or b in outb or c in outc or x in outx or y in outy or z in outz:

if a in outa:
a = random.randint(1,100)

elif b in outb:
b = random.randint(1,100)

elif c in outc:
c = random.randint(1,100)

elif x in outx:
x = random.randint(1,100)

elif y in outy:
y = random.randint(1,100)

elif z in outz:
z = random.randint(1,100)

print(all)

</code>

Answer 1

You might want to try using set's specifics here and get random unique values in this way:

from random import randint as r
b = set()
while len(b)!=6:
b.update({r(1, 100)})
print(b)

Set will increment its size only if the random value is different from the ones already in it. Which is pretty much what you want, if I understand it correctly.
Moreover, you also get them already sorted this way :)

Answer 2

I don't want to give a direct answer, because this is stuff you have to learn, but you should totally familiarize yourself with for-loops.

Answer 3

@Kuba Siekierzyński exactly what i wanted :) ty.

ps: find out that this does the same thing:

import random

print(random.sample(range(1, 100), 6))