what is output of given code void func(int x) { x+=6; } int main() { static int x; func(x); cout<<x; return 0; } // zero output explanation given below

Answer 1

it is 0 not because both variables are named x but because the copy of the value is being passed to the function. The original value of static int x is 0 after calling the function. If u want to change its original value pass it by reference put void func (int& x)

Answer 2

The Code Playground in SoloLearn outputs 0.

Answer 3

address of both variable named x are different
and if we r declearing any variable using static key word it automatically initialized as 0 so value of x in main function is zero so the output is zero

Answer 4

maybe it will be something like "undefined behaviour"

Answer 5

nothing as it is not returning any value to main

Answer 6

you're returning 0; all the other code is irrelevant in this context.

Answer 7

m not sure but if value of x is 0 then output is 6 (correct me programmers of m @fault) explain please

Answer 8

output 0

Answer 9

Static keyword specifies the value assigned to the variable is remains unchanged with in the scope of block.
Static variable's default value is 0.
Hence output is 0

Answer 10

correct ans is 0