how in boolean "banjoi" < "sanjo" returns true?

Question

banjoi has 6 letters while sanjo has only 5

Answer 1

It compares the ASCII code of the first character(letter) in words
b=98
s=115
So s>b
So it returns True

If the first character is the same , it compares second character(and so on)
so 'su'<'sv'

You can get the ASCII code of a letter using ord()
eg: ord("a") would give 97
And the letter associated with ASCII code can be retrieved using chr()
eg: chr(100) would give "c"

capital letters come before simple letters in ASCII table
so "S"<"s"

ASCII table is available in http://www.asciitable.com/
or Google it 😀

Answer 2

it's because 'b' comes bevore 's'

Answer 3

alphabetically, "banjoi" comes before "sanjo" therefore it is the lesser of the two.

Answer 4

great explanations thanks guys

Answer 5

if u want compare lenghts: len("banjoi")<len("sanjo")

Answer 6

run by dictionary

Answer 7

сложнаа