Can you have different variables with the same label eg. "x"? What is the printed value?

Question

In this code, what is the value of x after it's run:

Public void Main(args[]){
Int x = 5;
square(x);
print.ln(x);
}
Public void square(int x)
{
x = x * x;
}

Answer 1

The printed value will remain as 5, this is known as pass by copy. You're basically passing a copy of the variable "x" to another variable "x". With pass by copy the original value is inaffected however with pass by reference the original value will be affected.

Answer 2

5

Answer 3

when square method is called only a copy of x is passed to the method but in main x remains unchanged.so value of x remain 5.

Answer 4

x remains 5.
if you want to change the value of x, then you need little bit change

1- assign x: square(x);

2- method square must return int x;

Answer 5

For object variables, value is the address of the created object.

Answer 6

5 is the correct answer..
as u knw that u call a function square(x);
pass goes on to that function..
and new variable called x act as another variable for that square function which holds the value of previous x ie 5...
and if u want to see the changed value of x..
u just display in square function instead of main