Challenge: Check if array is ascending, descending or not sorted

Question

Input an array of number from user and check if the given array is in ascending order or descending order or not sorted.

e.g.

If the given array is 12, 13, 22, 27, 40 the program should print "Ascending".

If the given array is 45, 44, 23, 11, 11 the program should print "Not sorted"

and print "Descending" if the given array is in descending order.

Note: The array can be of any size but not less than 10.

Answer 1

https://code.sololearn.com/c7J540OFtYJz/?ref=app
Just done ! In C of course :p

Answer 2

I will do this challenge

Answer 3

Just need aome clearer definitions

Answer 4

Hope mine works
Function itself took 10 lines.
It was the getting input I was spending more time on.
https://code.sololearn.com/cDN4tlkZeY6O/?ref=app

Answer 5

Hope you like it

https://code.sololearn.com/cTNEVtyv5yon/?ref=app

Answer 6

Seems like we're all missing something important here; the initial instruction​ says the array is supposed to come as input from the user, and the list has to have at least 10 elements.

Answer 7

it wil work only if you enter all the six numbers

https://code.sololearn.com/chLW650w0Vc5/?ref=app

Answer 8

tis program accepts user input
if you have any suggestions comment it

https://code.sololearn.com/cwNkPP9kuVf5/?ref=app

Answer 9

something like this:
PS: 9 lines and O(n)

https://code.sololearn.com/cfia67RtNE9P/?ref=app

Answer 10

@Vengat Waiting...

Answer 11

Ask me if you have any doubt.

Answer 12

This challenge might interest you https://www.sololearn.com/Discuss/562254/?ref=app

Answer 13

https://code.sololearn.com/c6b0vG3UDi3h/?ref=app

My own answer

Answer 14

Here it is:
Works well.
https://code.sololearn.com/cSNDq0Gk0E58/?ref=app

Answer 15

@kartikey, no advertising in other threads please remove

Answer 16

Check out my challenge:
https://www.sololearn.com/Discuss/561399/?ref=app

Answer 17

We can use nested if statements
Like for descending order
if(n[0]>n[1])
{
if(n[1]>n[2])
{
.....so on up to n[9]>n[10]

}
}
for ascending order invert the signs(> to <)
else if
if none are true then it is disordered array

Answer 18

@/* S Vengat */ My code was very similar to your. But I had problems with the first if... Why do you have to put sorted(list (set (nums))) ? If the input is ascending, sorted (nums) should be equal to nums no?

Answer 19

Here you go. Works with both odd and even lengthed arrays
https://code.sololearn.com/cjAITs62otlO/?ref=app

Answer 20

the answer is in c language
#include<stdio.h>
int main()
{
int i,a[100],n,flag = 0,k=0,j=0;
printf("enter the number of elements");
scanf("%d",&n);
printf("enter the elements");
for (i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for (i=0;i<n-1;i++)
{
if ( a[i] < a[i+1])
k++;
else if ( a[i] > a[i+1])
j++;
}
if (k== n-1)
{
printf("they are in ascending order");
}
else if (j==n-1)
{
printf("they are in descending order");
}
else if (j<n-1||i<n-1)
{
printf("they are not ordered");
}

return 0;
}