What is the final value of y? //Program #include<iostream> using namespace std; int main() { int y; for(y=2;y<=6;y+=2) cout<<y; }

Answer 1

No, the increment is done at each loop except the first. Besides, if you look at the condition, you know that y has to be greater than 6 for the loop to end.

Here is the equivalent with a while loop:
int y = 2;
while (y <= 6) {
cout << y;
y += 2;
}

Answer 2

Okay. So it means that the value which will get printed will be 6, but the final value of y will be 8?
And Thanks!!

Answer 3

There is no spoon, I mean, no x.

If you mean y, the program will print 246 and the value of y will be 8 when the for loop ends.

Answer 4

That's right.

Answer 5

Shouldn't it be 6?? As it will be the last time the loop runs....