Confused on this variable declaration in PHP.

Question

So in a recent challenge for PHP I came across this line:

$var = !null == 1 || (5 ==9 % 3);

The variable $var equates to 1 after this declaration.

I had thought the answer would equate to a boolean, seeing as how the it's checking to see whether two different conditions are true. I'm clearly incorrect, but I still don't know why.

Answer 1

Never mind. I finally figured it out.

http://php.net/manual/en/language.types.boolean.php

PHP automatically converts any boolean to a value of '1' or '';

For example:

$var = 2 == 2;

echo $var; // This would print '1'

$var = 2 == 3;

echo $var; // This would any empty string.

This is not the case in something like python, where the first example would print 'True' and the second example would print 'False'.

Now I know.