+ 4
What does it mean ((c&&b)||(a||b))?
3 Réponses
+ 8
#include <iostream>
using namespace std;
int main() {
int a=-1,b,c;
b=++a; // b = 0
a=b++; // a = 0, b = 1
c=a; // c = 0
cout<<((c&&b)||(a||b)); // ((0&&1)||(0||1)) = 1
return 0;
}
+ 7
0 and 1 = 0
0 or 1 = 1
start your assessing from inside pranthesis
+ 1
@Babak thank you