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A number P, when separately divided by 7 and 9, the remainders are the first two natural numbers respectively. What is the P ??

4th Sep 2017, 3:35 PM
Ashutosh Mishra
Ashutosh Mishra - avatar
11 Réponses
+ 10
natural no. starts from 1 so ur answer is wong @ winfrjd & p = 7n +1 = 9 m+2 n=(9m+1)/7 now put m as 1 ,2,3...and check where n comes an integer .. soon the game will be over ☺ bcz m,n are integer (+ve) edit : game is over ... ie 29 //29 is the answer 😂
4th Sep 2017, 4:01 PM
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+ 9
actually , whole number starts from 0 and natural nos starts from 1 ... sorry if i sounds rude but thats not even primary level maths
4th Sep 2017, 4:07 PM
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+ 9
answer will be 29 instead of 28 from my side ... @winfrjd bro .. sometimes i become rude 😕 ...
4th Sep 2017, 4:19 PM
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+ 9
lets wait for ashutodh 2 come ☺ , anywYs nice meeting u , bye ...
4th Sep 2017, 4:21 PM
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+ 8
google it
4th Sep 2017, 4:06 PM
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+ 8
//okh u won ,u can use 0 as natural no... but i can't anyways gr8 knowledge sir 👍
4th Sep 2017, 4:10 PM
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+ 4
"texts that exclude zero from the natural numbers sometimes refer to the natural numbers together with zero as whole numbers, but in other writings, that term is used instead for the integers (including negative numbers". I see the positive effect of standarization, so I follow ISO 80000-2. It looks like this question has two answers, depending on the definition of natural numbers used. We are both right. Congrats!
4th Sep 2017, 4:15 PM
winfrjd
winfrjd - avatar
+ 3
28
4th Sep 2017, 3:49 PM
winfrjd
winfrjd - avatar
+ 3
According to ISO-80000-2 they start with 0, corresponding to the non-negative integers.
4th Sep 2017, 4:04 PM
winfrjd
winfrjd - avatar
+ 3
I did
4th Sep 2017, 4:06 PM
winfrjd
winfrjd - avatar
+ 2
29
5th Sep 2017, 12:34 PM
Ayan