Give and explain the output of the following? int main () { int i, n = 4; for (i = 0; i++<n; i++) cout<<i<<"i"; }

Answer 1

i is set to zero in the beginning , the condition is checked first (i++<n) and while checking the codition i is "incremented" by 1.. so now the value of i is "1"...the loop runs for the first time,and 1i is displayed in the console and i is incremented again after the end of loop..now i="2",loop runs again and "i" gets incremented again while checking for the condition (i++<n) ,now i="3" and 3i is displayed the console and as the loop ends ,"i" gets incremented again but now i is 4 which means i++ should be 5..and 5 is not less than 4 so loop will not run again..program ends here after returning zero

Answer 2

1i3i
You can try to run the code in the Code Playground and see how it works :)

Answer 3

n=4 i i <=n i++(i=i+1)
0 true 1
1 true 2
2 true 3
3 true 4
4 true 5
false
It prints value of i on the screen till the condition is satisfied i.e. 0 1 2 3 4

Answer 4

I didn't get u

Answer 5

"first u learn english"@sukhvinder

Answer 6

the output will be
1 i
3 i

Answer 7

Помогите, гайд по c++

Answer 8

it is i

Answer 9

I am not understand