Can I determinate the number of input before require them ?

Question

I want to determine the number of inputs before require/use them.
(example)
ask = int (input ('How many people are in the room ?')
#ask = 2

p1 = int (input ('Type age: '))
p2 = int (input ('Type age: '))

(because the number of persons are two).

But if was 120, each one with a different age ?
#ask = 120
p1 = int (input ('Type age: '))
p2 = int (input ('Type age: '))
...
pn = int (input ('Type age: ')) (n times)
And I need use this "pn" inputs.
ask = 2
res =( p1 + p2 ) / 2
ask = n
res = (p1+..pn)/n

Answer 1

You can just ask for the persons' age in a loop and put the results in a list. So first you ask for the number of people the way you already do. That gives you the number n. Now you can do this:

persons = []
for i in range(n):
persons.append(int(input('Type age: ')))

You can then access the age of e.g. p1 via persons[0].