Whats the output

Question

a = 9; b = 20; temp = a / b * 2 % 2 + Math.floor(Math.random()*5);

Answer 1

You should include a language tag. Is this Java or Javascript? They both have a Math.random() and a Math.floor(). Fortunately they both behave in a similar fashion. Math.random() will return a floating point number from 0 to 1 (exclusive). Meaning the highest number returned will be 0.99999.
If you multiply .99999 * 5 you get 4.9999 then you take the Math.floor() of this number which will cut everything after the decimal point off. This means that you will get a pseudo random integer from 0 to 4.

* is used for multiplication
/ is used for division (integer division in Java)
% is used to get the modulus (division remainder) (example 9/4 = 2 with a remainder of 1 so the modulus is 1) (When the numerator is smaller than the denominator then the modulus is the numerator I.E. 5 % 7 = 5

a = 9;
b = 20;

temp = a / b * 2 % 2 + Math.floor(Math.random()*5);

a/b is 9/20 = 0.45 in JavaScript or 0 in Java (This is why it is important to tag the programming language) (from here on down I'm going to assume JavaScript unless you specify otherwise)

0.45 * 2 = 0.9
0.9 % 2 = 0.9
Which leaves you with a number that is equal to 0.9 + a random integer from 0 to 4, or a number from 0.9 to 4.9. Possible answers are 0.9, 1.9, 2.9, 3.9 and 4.9.

Answer 2

JavaScript

Answer 3

The output will be ranging from 0..5