What is a output and how ?

Question

void main ()
{
int x,a,b,c;
a = 2; b = 4; c = 5;
x = a-- + b++ - ++c;
printf("x: %d",x);
}

Answer 1

First, thanks for clearing the irrelevant links, now I'll try to explain it, I will assume you understand the first 2 lines, as they are just variable declaration, and value assignment.

The result is zero, because in the line where the calculation is done, a & b still have their previous value, only c is incremented instantly, because it is the only operand calculated using the pre-increment.

void main ()
{
int x,a,b,c;
a = 2; b = 4; c = 5;

// x = 2 + 4 - 6
x = a-- + b++ - ++c;
printf("x: %d",x);
}

Hth, cmiiw

Answer 2

I'll answer if you remove those irrelevant links from your question :)

Answer 3

You're welcome :)

Answer 4

????

Answer 5

kk

Answer 6

what is the output of this program

Answer 7

and how

Answer 8

ok thanks