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[SOLVED] Why is 16 not printed in this code when breaking is only when i == 32?

Tried while loop with two if statements . original value of i = 1. then i = i*2. to continue till i <= 10, then breaking at i = 32. result was 2, 4, 8, breaking, finished.

28th Oct 2017, 6:40 PM
prema
3 Réponses
+ 7
If you are referring to the code below: https://code.sololearn.com/cdhCygSbUI6H/?ref=app It only prints when i < 10, so the last is 8 When it reaches 16 it does not meet the first condition (as 16 > 10) and goes without doing anything, back to the beginning of the loop. Then it gets doubled to 32 and breaks. Anything that stands after the break statement cannot be executed.
28th Oct 2017, 9:24 PM
Kuba Siekierzyński
Kuba Siekierzyński - avatar
+ 1
Thanks a lot Kuba for the explanstion. now it's clear.
29th Oct 2017, 2:17 AM
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0
can you share or copy the code maybe ? wild guess is that you continue or dont print anything after i <= 10
28th Oct 2017, 6:56 PM
Chrizzhigh
Chrizzhigh - avatar