Generate a 64 byte hex number

Question

I want to generate a 64 byte hex number with a recurring pattern but would prefer not to enter a loooooooong string and I may want 128 byte equivalent at a later date

hex_inner = 0x5c5c5c5c5c.............

Is there a way to populate hex_inner with a short format statement....

Answer 1

You can do it with bit shifting.

hex_inner = 0
for i in range(0,64):
hex_inner |= 0x5c << (i * 8)

Answer 2

Thanks for that much appreciated