C program for Swapping two numbers

Answer 1

Swapping two numbers

#include < stdio.h >

int main()
{
  int x, y, temp;

  printf("Enter the value of x and y\n");
  scanf("%d%d", &x, &y);

  printf("Before Swapping\nx = %d\ny = %d\n",x,y);

  temp = x;
  x = y;
  y = temp;
/*using temp to swap
storing x to temp and y to x then moving temp to y*/

  printf("After Swapping\nx = %d\ny = %d\n",x,y);

  return 0;
}

Answer 2

if yiu don't want use a third variable temp try this one instead

/* same code */

a=a+b;
b=a-b;
a=a-b;

/* same code */

Answer 3

You can also use this code using bitwise xor operator (^)

a = a ^ b;
b = a ^ b;
a = a ^ b;

I think this is the best way to swap 2 numbers

Answer 4

a=a+b-(b=a)

this is a simple one line logic

without using a third variable

Answer 5

{
int a,b;
printf("enter number");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("a=%d b=%d",a,b);
}

Answer 6

by using:-
a=(a+b);
b=(a-b);
a=(a-b);
swaps the two numbers....
if a=2; and b=10;
then by using swaps method as mentioned above...
a=10; and b=2;

Answer 7

it can be done by more than 20 ways....

Answer 8

Swapping two numbers

#include < stdio.h >

int main()
{
  int x, y;

  printf("Enter the value of x and y\n");
  scanf("%d%d", &x, &y);

  printf("Before Swapping\nx = %d\ny = %d\n",x,y);

  x=x+y;
y=x-y;
x=x-y;
/*without using temp to swap
storing x to temp and y to x then moving temp to y*/

  printf("After Swapping\nx = %d\ny = %d\n",x,y);

  return 0;
}