How to identify a integer number is +ve or - ve without if-else

Answer 1

cout << (unsigned(a) <= unsigned(-1)/2 ? "+" : "-") << endl;
For any int a.
If you dont want to use any conditional:
bool isPositive = unsigned(a) <= unsigned(-1)/2;

Answer 2

you can do it with switch case also

Answer 3

the first bit of any variable of basic signed datatype represents the sign

Answer 4

Not first bit, last bit MSB represents sign and then how to write program

Answer 5

is it the left-most bit you are referring to in a binart number?

Answer 6

i want without / % operators

Answer 7

conditional expression ? : equivalent to if-else

Answer 8

#include <limits.h>
int main() {
int a = -9;
bool isPositive = unsigned(a) <= INT_MAX;
return 0;
}

Answer 9

using relation operator in a statement is similar to if-else
<= will generate if-else condition

Answer 10

int a = -1;
bool isPositive = ~a & (1 << 8*sizeof(a) - 1);
I hard coded the number 0x1f (31) and i dont like that because ints can be other size than 32 bits but I think this will do it.
Edit:
Corrected.

Answer 11

use sizeof operator to identify int size