Why is the function not launching when user types in either pizza or taco?

Question

def taco():
print("taco")
def pizza():
print("pizza")

choice= input("taco or pizza")

if choice =="taco":
taco()
elif choice =="pizza":
pizza()
else:
print("fail")

Answer 1

What is your input/output?

Answer 2

I copied it but it still executes the fail.

Answer 3

actual python

Answer 4

how different is cpython and qpython I can't find an app for cpython

Answer 5

so why doesn't the same thing work on both

Answer 6

now it's just giving me an error after I copied your new edit it's supposed to be simple to make sure the functions are working it's becoming more complicated than it should be