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  list = ['a', 'b', 'c', 'd']   print list[1:-1]   ## ['b', 'c']   list[0:2] = 'z'    ## replace ['a', 'b'] with ['z']   print

plz explain this .

16th Nov 2016, 12:49 AM
subhan d
subhan d - avatar
1 Réponse
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1. indexes in python start from 0, so list[0] = 'a' 2. negative indexes start counting backwards from the last element, that's why list[-1] = 'd' 3. when slicing a list ( print list[1:-1] ), the first position is included and the last is excluded 4. list[1:-1] starts from index 1 which is 'b' and goes to index -2, because the last position mentioned (-1) is excluded ( see point 3 ) 5. list[0:2] = 'z' does an assignment to elements on index 0 and 1 ( because of point 3 from above ) with the value 'z' Cheers
16th Nov 2016, 2:05 PM
Andrei R
Andrei R - avatar