Can some Body Solve this Tipical Logicall error

Question

#include<iostream>
#include<conio.h>
#include<math.h>
using namespace std;
int main()
{

int a,b,c,x,lar,slar,tlar; //a b c are sides of triangle
cin>>a>>b>>c;
do{

if((pow(a,2)+pow(b,2)==pow(c,2))||(pow(b,2)+pow(c,2)==pow(a,2))||(pow(c,2)+pow(a,2)==pow(b,2)))
{
x=1;
if(a>b)
{
if(a>c)
{
lar==a;
slar==c;
tlar==b;
}
else
{
lar==c;
slar==a;
tlar==b;
}
}
else
{
if(b>c)
{
lar==b;
slar==c;
tlar==a;
}
else
{
lar==c;
slar==b;
tlar==a;
}
}
float sin,cos,tan;
sin = tlar/lar;
cos = slar/lar;
tan = tlar/slar;
cout<<"H"<<lar;
cout<<"B"<<slar;
cout<<"P"<<tlar;
cout<<0<<"=\t"<<sin;
cout<<0<<"=\t"<<cos;
cout<<0<<"=\t"<<tan;
int rootfive,theta;
rootfive=sqrt(5);
theta=(lar*rootfive)/tlar;
cout<<0<<"\t=\t"<<theta;
}
else {
cout<<"wrong entry";
break;
}
}while(x!=1);

return 0;
}

Answer 1

One basic difference between "==" operator and "=" operator is "==" operator is "equality operator" and is used for comparing the value on right side of "==" operator is equal to the value on left side of the operator.
While "=" is the "assignment operator" and is used to assign value on right side of the operator to left side variable.

Solution:
In the above code in if-else cases when u are assigning values of a,b,c to lar, slar, tlar instead of using "==" operator use "=" operator.
This should solve your logical error.

Please correct me in m wrong, looking forward for your inputs. ^_^