Why this is invalid syntax, can someone explame?

Question

x = 1
a = input("Your number")
if x = a:
print("good")
else:
print("bad")

invalid syntax is "if x = a:"
Why? im trying a mini guess number game but its not this code there need import random and i know how all need do but when i put input in "if" it says invalid syntax and dont know way how to fix it or i do something bad? Ty i wait for answer who can explame me :)

Answer 1

= is an assignment operator, meaning you are assignment x to that value, thus the if is always true. use == when doing a comparison.

Answer 2

that is saying if x is greater than a. Sorry if I don't understand your question correctly. Is > also giving you invalid syntax?

Answer 3

Oh your a is not an integer, that's why > was giving you an error.

Answer 4

Thanks u for this answer! now i understand. Oh one more question. How do with > or <? like "if x > a:" its same

Answer 5

i figured out :) need add int()

Answer 6

no no hm. mine english bad.. i want do guess number game. i import random
ex

import random
a = input("number")
b = random.randint(1, 10)

when i write
if a > b:
print("number too high")

and in if a > b: gives error dont know why

Answer 7

thanks u i figured out ! soon post working guess number game ofc if i done it correctly :)

Answer 8

when using input(), the data read in is put into a string variable, even if you only give it an integer. I haven't delved too much into python yet, but I'm sure there's a way to convert the string to an integer or the other way around, but type conversions like that are not guaranteed to work flawlessly.

Answer 9

Posted in playgroud guess number game ! my first good code ^^ go check :)