Discussions Q&R
Can anyone tell me the code in java about write a function which returns true for two arrays have same unique elements? Thanks!!
0 Vote
9 Réponses
Can somebody explain to me how can a boolean have a value other than true or false in ruby? Truthies and falsies I mean.
0 Vote
1 Réponse
There is a wrong answer.
-1 Vote
2 Réponses
Comparison operator
1 Vote
1 Réponse
>>> def even(X):
... if X % 2 == 0 : return True
... else: return False
...
>>> filter(even, [0,1,2,3,4,5,6])
[0,2,4,6]
How to get that output, help please...
0 Vote
3 Réponses
def my_func(n,i,c):
if i==0:
if c==2:
return True
else:
return False
if n%i==0:
c=c+1
return n,i-1,c
n=int(input())
ans=my_func(n,n,0)
if ans==True:
print ("prime")
else:
print('not prime')
0 Vote
1 Réponse
(true + false) > 2 + true
7 Votes
4 Réponses
why is 'senior' still outputted in this case? I understand that '42' and 'default' outputs because the criteria matches and there is no break, but 'senior' is still false is it not?
2 Votes
3 Réponses
Bools and pointers
1 Vote
15 Réponses
While (0&&0) Question
3 Votes
5 Réponses
ایرانیا کمک
0 Vote
1 Réponse
Why y does not change?
3 Votes
7 Réponses
Why output is False?
2 Votes
6 RéponsesHow do i fix my Sign up
1 Vote
1 Réponse
pairs = {1: "apple",
"orange": [2, 3, 4],
True: False,
None: "True",
}
print(pairs.get("orange"))
print(pairs.get(1))
print(pairs.get(12345, "not in dictionary"))
the output is
［2, 3, 4］
False
not in dictionary
why is print(pairs.get(13345,"not in dictionary")) giving the output not in dictionary.pls I nid explanation
2 Votes
4 RéponsesWhen dealing with propagation, if you set a <div> element to true, meaning it will use capturing, but set a child element, say <p>, to false so it uses bubbling, which event will take place first?
1 Vote
2 Réponses
need an advice
1 Vote
2 Réponses
Bool function problem
1 Vote
1 Réponse
x = 42;
int num = 0;
while (num <3)
Consele.writeline (x);
num++;
int x = 42; is just an int with an asigned value of 42
int num=0; is what initiate the count for the while loop
while (num < 3); means 0<3 true, 1< 3 true, 2<3 true, the loop end at 2 bc 3 <3 is false
consele.writeline (x) will display 42 while num < 3
num++ will execute and then add 1 to check if the while loop still true, but it stop at 2, bc 3 makes it false.
so the consele.write will write 42 three times. x=42, remember the (x)
0 Vote
2 RéponsesHow can I make a reference for a list of variables. If false i want the system to check through all my variable to make sure they are false.
Code-
var2 = "Tanner"
var3 = "Jake"
question = input('What is your name? ')
if question == var2:
print('\nWelcome Back Tanner!')
if question == var3:
print('\nWelcome Back Jake!")
if question !=( This is where i need help!)( Is the != the correct way to write not equal?)
0 Vote
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