0

I have a code which is a little confusing.See it below...Can some one tell me how it executes step by step?

15th Jan 2018, 5:06 AM
Noperson
Noperson - avatar
2 odpowiedzi
+ 1
// Create TwoThree object storing it as a SubTwoThree SubTwoThree t = new TwoThree(); // Call the void g(long x) {f(x);} of SubTwoThree with 20 // Call the void f(int x) {System.out.println("int in S: " + x);} of TwoThree as it overrides the SubTwoThree version with 20 // Output "int in S: 20" t.g(20); // Call the void g(long x) {f(x);} of SubTwoThree with 20L // Since there isn't a void f(long x) function of SubTwoThree automatically convert to double which does exist // Call the void f(double x) {System.out.println("double in T: " + x);} with 20.0 // Output "double in T: 20.0" t.g(20L); // Since there isn't a void g(float x) function of SubTwoThree automatically convert to double which does exist // Call the void g(double x) {f(x);} of SubTwoThree with 3.5 // Call the void f(double x) {System.out.println("double in T: " + x);} with 3.5 // Output "double in T: 3.5" t.g(3.5f); // Call the void g(double x) {f(x);} of SubTwoThree with 3.5 // Call the void f(double x) {System.out.println("double in T: " + x);} with 3.5 // Output "double in T: 3.5" t.g(3.5);
15th Jan 2018, 5:52 AM
John Wells
John Wells - avatar
0
class TwoThree { void g(int x) { f(x); } void g(double x) { f(x); } void g(long x) { f(x); } void f(int x) { System.out.println("int in T: " + x); } void f(double x) { System.out.println("double in T: " + x); } } public class SubTwoThree extends TwoThree { void f(int x) { System.out.println("int in S: " + x); } void f(long x) { System.out.println("long in S: " + x); } public static void main(String[] args) { TwoThree t = new SubTwoThree(); t.g(20); t.g(20L); t.g(3.5f); t.g(3.5); } }
15th Jan 2018, 5:06 AM
Noperson
Noperson - avatar