Can anyone explain the output?

Question

#include <iostream>
using namespace std;

int main() {
int x=1,y=1,z=1;
cout<<(++x||++y&&++z);
cout<<x<<y<<z;
return 0;
}

Answer 1

I’m not sure how C++ handles integers as booleans, but the second cout will output 222 because x y and z were incremented in the line before.

Answer 2

No, the compiler doesnt have to test z because the OR-Condition will always be true if one operand, here x, is true. Whether z is true or false simply doesnt matter for the compiler, so he skips checking it. Did you read through the post I linked? I explained it in detail there...

Answer 3

Here you find a similar case that should aswer your question:
https://www.sololearn.com/discuss/992610/?ref=app

Answer 4

i can't understand why z is not incremented

Answer 5

In ++x||++z only x is increased and result is one but after that to evaluate and second condition must be checked i.e ++z

Answer 6

ohk now i understand the precedence of && is greater than ||. Thanks for helping