it can b more simple or not I'm not getting

Question

y= int(input("enter a num:\n"))
print (y)
if y==11:
print("it is 10 or more than 10 ")
elif y==0:
print("but y is even 0")
elif y==1:
print("but y is odd 1")
elif y==2:
print("but y is even 2")
elif y==3:
print("but y is odd 3")
elif y==4:
print("but y is even 4")
elif y==5:
print("but y is odd 5")
elif y==6:
print("but y is even 6")
elif y==7:
print("but y is odd 7")
elif y==8:
print("but y is even 8")
else y==9:
print("y is odd 9")

Answer 1

In my opinion you could check first if it's even or not and then print what it is and the y value separately, and maybe don't print the value at the beginning because you are printing it again later.

Answer 2

y= int(input("enter a num: "))
s=y%2
if (s==0):
print("the num is even")
else:
print("the num is odd")
print(y)

Answer 3

I'll try it😊

Answer 4

#include <iostream>
using namespace std;

int main()
{
int x;
for( x=1;x<10;x++)
cout <<"haris"<<endl;
return 0;
}
I did like this I'm getting haris as output for 10 times🙎
I thought that this u were going to do!!!☺......