How To Accept A Value In Java After System.out.println?

Question

JAVA

Answer 1

import java.io.*;

public class Program
{
public static void main(String[] args) {

String playerName;
StringBuffer buffer = new StringBuffer();
BufferedReader nameReader = new BufferedReader(new InputStreamReader(System.in));
playerName = null;

System.out.println("Insert player name:");

try
{
playerName = nameReader.readLine();
buffer.append(playerName);

}
catch(Exception ex)
{
ex.printStackTrace();
}
System.out.println("Your name is "+playerName+" ,right?");
}
}

Answer 2

import java.util.Scanner;

System.out.println("type a value");
Scanner scan = new Scanner(System.in);

String value = scan.nextLine();

System.out.println(value)

Answer 3

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
System.out.println("Please enter your name");
Scanner name= new Scanner(System.in);
String nam;
nam=name.nextLine();
System.out.println("Your name is "+nam);
}
}
You have to use Scanner class(there are other class also) to take input. It is written in basic concepts of java please complete tutorial.

Answer 4

He wanted to know how to take input, it does not matter which data type or what is length of input.

Answer 5

using Scanner.next() would actualy only get the first word of the input

Answer 6

Just saying that nextLine would be more apropiated in your example

Answer 7

In InputStreamReader And BufferedReader?

Answer 8

In InputStreamReader?