Python Programmers What Is This Permission os.chmod(sys.argv[0], 3) ?

Question

I was boring so I tried this on PyDroid 3 :
os.chmod(sys.argv[0], 3)

in PyDroid 3 the system.argv[0] is running as the script file and the hackrun file so after I used that code it just outputs :
Traceback most recent calls/last
File:arm-linux-adnroid/accomps_files/iiec_hackrun/hackrun.py
exec(open(fakepyfile).read(), __main__.__dict__)
PermissionError[errno13]: Permission Denied

I reinstalled PyDroid 3 and it's libraries so what is the permission ? os.chmod(sys.argv[0], 3) ?

Answer 1

As I get it, you changed your own permissions to the file under execution to write and run. And the parser wanted to *read* thus failed.

Answer 2

@patel I didn't mean why preferring python I mean what is this permission os.chmod(sys.argv[0], 3)

Answer 3

@Kuba Thanks sir :)

Answer 4

@Kuba Siekierzynsky is there is any list for those integer chmods in python when it tells you to use a number of a permission

Answer 5

Yes, for example:
https://www.linux.com/learn/understanding-linux-file-permissions

Answer 6

#Trythis question

https://www.sololearn.com/Discuss/1069156/?ref=app