How do I? (help please) : while statements with multiple conditions

Question

So here is my question :
int a, b, x, y;
while (a!=x & b>y){
if (a>=2x){
b=(y-1);
cout << "statement0" << endl;
cin >> a;
if (a==x){
cout << "statement2" << endl;
}
}
else{
if (a==x){
cout << "statement1" << endl;
}
}

/*Q. when the first if statement triggers that sequence, and where a==x gets (statement2), how do I make it so that the (statement1) from the else statement also doesn't show up?*/
example of result:
when initial a>=2x:
"statement2"
"statement1" (//which is not what I want, 2 statements appearing)
but when initially a==x:
"statement1" (//which is what I want, just a single statement)
(this is a not the original code, it does ask for user input, and I use 2x to help visualize that when I set the conditions for twice the value of x or a value greater than x.)

Answer 1

anyway, I figured it out, I just have to put the if statement where a==x in front of the if statement where the condition of a>=2x is met.

Answer 2

this is a simplified version of the problem i'm having, but all in all, in the original code, it does ask for user input, and 2x is just merely a statement i'm using to help visualize the problem.
Also I did state that it DOES work so that must mean I did it right, the only part i'm having trouble is allowing it to set priority of these 2 statements being synonymous.

Answer 3

I don't know a lot about c++, but some things in this code arent valid/good, like you dont ask for user input to check if a!=x or b>y.

If you want to say "and" you should use 2 &s, so like this (&&);

Also, 2x isn't valid like in math, you should use 2*x.

Hope that someone will help you solve this, or you could first ask for user input
something like:

cout << "enter a number: " << endl;
cin >> a;
....
cout << "enter the last number: " << endl;
cin >> y;
...