Why is it showing 4 in output?

Question

int[ ][ ] myArr = { {1, 2, 3}, {4}, {5, 6, 7} };
myArr[0][2] = 42;
int x = myArr[1][0]; // 4

Answer 1

You declared a two dimension array with 3 rows and (partially) three columns;

Column 1 2 3 ... n
Row 1 {1,2,3}
Row 2 {4}
Row 3 {5,6,7}
...
Row n

Because we use zero based index to refer to array elements, myArr[1] [0] refer to the first column of the second row.

P.S. Exactly as @Danilo explained : )

Answer 2

In most programming languages, the first element of an array has index '0'; the second element has index '1' and so on. myArr[0][2] refers to the third element ([2]) of the first array ([0]). So basically, you first need to know which array you are talking about, and then you go after the element of that array, i.e., someArray[array][element_of_array].

Answer 3

got it!
thanks