I need help understanding what is going on with this recursion problem

Question

Could some one explain to me how does this code out put 26

def decor(a,b):
def sq(func):
return func(a,b)*func(a,b)
return sq
def subs(a,b):
return(a-b)
def add(a,b):
return (a+b)
f = decor(2,3)
print(f(add)+f(subs))

Answer 1

the function decor builds a function sq.
a,b --> sq(func)

f is
f(func):
return func(2,3)*func(2,3)

f is called twice:

f(add) returns add(2,3)*add(2,3)
= 5*5

f(subs) returns
subs(2,3) * subs(2,3)
=(-1)*(-1) =1

Answer 2

(2+3)**2 + (2-3)**2

Answer 3

yes

Answer 4

Line 3 outputs func**2. It's the same as func*func.

Answer 5

I see ... is it because sq(func) = func**2

Answer 6

@oma Falk
Could you please explain to me which part of the code that outputs **2?