(Help) Foreach loop

Question

int[] a={1,2,3,4,1};

for(int n:a)
a[n]=0;
for(int n:a)
System.out.print(n+" ");

Output is 0 0 3 0 1
How?? And WHY???

Answer 1

'n' contains value which is stored in 'a'. The index position at 'n' is set equal to zero. So in the beginning, 'n' is 1 and the 2nd element (a[1]) of the array is set to 0. And so on. 'n' doesn't increase from 0 to length of array.

Answer 2

Try this code. It prints the array every time it loops.

https://code.sololearn.com/csVpSjE071EJ/?ref=app

Answer 3

I don't want to make everything 0... I want to know why the values of n are 0 0 3 0 1...indexing starts from 0,1,2....so on... But here indexing is 0 0 3 0 1..why it so??

Answer 4

Even though you explained me, its hard to understand at the very next moment. But i got that..
You are a good geek😁😁
Thank you tejaswi...😊

Answer 5

if you want to make everything 0, do this:
for(int i = 0; i < a.length; i++) {
a[i] = 0;
}