Why Inputing "#" in "gets.chomp.to_i" won't crash the code?

Question

I noticed that even if the input of first_num and secone_num had a hash sign(#) in it, the code still runs correctly.
Ex:
If the input was :

5 #3
*
6 #2
done

The output will be: 5*6=30
But if the operator input had a hash sign ex : * #+ it is printed and the code won't execute correctly(even though it shows no Errors).
I am confused 🤕

Why it works? Why no error was raised?
Why the second try didn't work? And why no error was raised in the second try?

https://code.sololearn.com/ciE5vXdom3Eh/?ref=app

Answer 1

The to_i method returns an integer no matter what. Input of '#' would yield a 0, '5#' a 5. It stops looking at the first non-digit and returns whatever it did find.

Your operator string can only be matched to your test string exactly. Anything extra and it fails. Therefore, no math is performed.

Answer 2

@John Wells
Thank you, sir.
I get it now