Reverse integer number with while loop

Answer 1

no just reverse every single character of number like
input : 768
output : 867

Answer 2

Its very simple 1. Convert integre to character array
2. Use inverse character array like this code

#include <stdio.h> // printf
#include <stdlib.h> // malloc, free
#include <string.h> // strlen
int main()
{ char* s = "hello";
size_t l = strlen(s);
char* r = (char*)malloc((l + 1) * sizeof(char));
r[l] = '\0'; int i; for(i = 0; i < l; i++) { r[i] = s[l - 1 - i]; } printf("normal: %s\n", s); printf("reverse: %s\n", r); free(r); }

Finally return it to integer like this code

char myarray[5] = {'-', '1', '2', '3', '\0'};
int i;
sscanf(myarray, "%d", &i);

Answer 3

https://code.sololearn.com/chhVtwlgKVLD/?ref=app

Answer 4

What do you mean? Like reverse an array of ints?

Answer 5

One sec I’ll write the code for you

Answer 6

int num = 768;
std::string s = std::to_string(num);
std::string reverse = “”;
char cstr[] = s.c_str();
int i = 0;
while (s.length() != reverse.length()){
i++;
reverse += cstr[cstr.length()-i];
}

Answer 7

This would be much easier done with a for loop or just using methods

Answer 8

And at the end just convert reverse to an int

Answer 9

decreasing integer loop