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Int a; for(a=2; a<=50;a+=2) {If( a != 10 and a != 20) cout<<a;} why the program still output value 10 and 20 in looping?

I confused process looping ?

9th Dec 2016, 6:52 AM
Dicki Andrea
Dicki Andrea - avatar
3 odpowiedzi
+ 1
Are you using c++? If you are then your code is wrong. In c++, there is no "and" operator. Hence in an if statement, if you want more than one condition, then you have to use the && operator instead of the word "and". So the code looks like this in c++ #include <iostream> using namespace std; int main(){ int a; for(a=2;a<=50;a+=2){ if((a! != 10 && a != 20){ cout << a << endl; } } return 0; }
9th Dec 2016, 9:34 AM
Eddy
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Thanks Eddy for your answer, but my trouble not in that code c++ but in the output of program. Because while i simulate the code in manual, values 10 and 20 it must still write in output. because if a = 10, it will be false for a != 10 and will be true for a != 20. So, the output is false, because false and true = false.
9th Dec 2016, 10:57 AM
Dicki Andrea
Dicki Andrea - avatar
0
But, if i compile the code in compiler the values 10 and 20 is not write in output
9th Dec 2016, 11:00 AM
Dicki Andrea
Dicki Andrea - avatar