[CHALLENGE] Get all array permutations without mirrored cases

Question

All languages are welcome (JAVASCRIPT preferable).

Example

Input: [true, false]
Output: true, false //"false, true" is the same one since it is a "mirrored" case

Input: [a, b, c]
Output: abc, acb, bac

Answer 1

bca is a mirror of acb. [Lucas updated]

Answer 2

My version
https://code.sololearn.com/cq5o5e3wo5s9

Answer 3

Fixed, then.

Answer 4

Lucas Sousa Shouldn't the output be nothing for the input a,a,a,a,a,a,a,a ? This is as aaaaaaaa is a mirror image of aaaaaaaa as well, so I think an empty set should be returned.

Answer 5

My Try :
https://code.sololearn.com/cSYIZ76443oV/?ref=app

Answer 6

First n!/2 permutations is bad because if we have a array such as

[a, a, a, a, a, a, a, a]

will be returned too many equals cases once we just have 1 case ('aaaaaaaa').