+ 3

Why is this the result

Why when i do: A = [1,2,3,4,1] for n in A: A[n]=1 print(A) It only modify 3 things in the list

18th Jun 2018, 3:25 AM
Ffff
4 odpowiedzi
+ 3
On first loop: n is 1. So, "A[n] = 1" means A[1] = 1 So, A becomes [1, 1, 3, 4, 1] On second loop: n is STILL 1 because the second number of "A" list is 1 So, "A[n] = 1" means A[1] = 1 So, A remains as [1, 1, 3, 4, 1] On third loop: n is 3 because the third number of "A" list is 3 So, "A[n] = 1" means A[3] = 1 So, A becomes [1, 1, 3, 1, 1] The rest of the loop doesn't impact anything much. So, that's why it modifies only 3 things in the list
18th Jun 2018, 12:13 PM
SomeOne
+ 5
1: A = [1,2,3,4,1] 2: for n in A: 3: A[n]=1 4:print(A) First time in loop line 2 & 3 n=1 so A=[1,1,3,4,1] Second time in loop n=1 so no change to A Third time in loop n=3 so A=[1,1,3,1,1] Fourth time in loop n=1 so no change to A Fifth time in loop n=1 so no change to A
18th Jun 2018, 4:17 AM
John Wells
John Wells - avatar
+ 2
1st time it is modifing A[1] which is 2 basically 2nd time it is modifying A[1] which is changed to 1 earlier 3rd time it is modifying A[3] which is 4 basically 4th time it is modifing A[1] which is already 1 5th time is is again modifying A[1] hence it is modifying only 3 times
18th Jun 2018, 4:19 AM
PRAMOD JANA
PRAMOD JANA - avatar
0
Thanks
18th Jun 2018, 12:19 PM
Ffff