Is there any bug in the code below? I am solving the problem number 1044 from URI online judge.

Question

#include <stdio.h>

int main() {int A,B;
scanf("%d %d",&A,&B);
if(A%B==0 || B%A==0);
{printf("%Sao Multiplos\n");}
else {printf("Nao sao Multiplos\n");}
return 0;
}

Answer 1

There is semi colon after the if condition and printf ("%???what?") there is a format specifier missing with what value you want to print.

Add some spaces and line breaks for better readability.

Answer 2

you can use %d format specifier

Answer 3

Thanks Akib Reza ...The program ran successfully

Answer 4

Which format specifier should I use?

Answer 5

#include <stdio.h>

int main() {int A,B;
scanf("%d %d",&A,&B);
if(A%B==0 || B%A==0)
{printf("%Sao Multiplos\n");}
else {printf("Nao sao Multiplos\n");}
return 0;
}

Answer 6

After running the program I have noticed that a 1 or 0 is printed in the output.. But I don't want to print them. What can I do now?

Answer 7

// Why you have inserted % below???
printf("%Sao Multiplos\n");

Anyway i also making challenges there and i use codechef for online compiling

Answer 8

KrOW It was a typing mistake.. By the way thanks

Answer 9

Can you save your code on Code Playground section and post here his link? In this way we can run it

Answer 10

Mehrin Jahan I have seen your code and ITS not the same that you have pasted... In your printf remove the format strinf param "%d" and you will see that no int will output... Please next time post your code link directly