Explain how it is?

Question

Need explanation of java code, how it works?

https://code.sololearn.com/cdzcAKTDsREl/?ref=app

Answer 1

let's explain it line by line:

class CourseCube{
// Simply create a class

public static void main(String as[]) {
int X=10;
// initial value of x = 10

int Y=X++ + ++X;
// post increment of x + pre increment of x. x changes value from 10 to 12 as : when x++ is written x gets incremented for next time it's called and then when we write ++x x gets incremented because of previous increment and once again due to post increment so x becomes 10 + 1 + 1 = 12. Furthermore y will be 10 + 12 = 22

System.out.println("X = "+X);
// prints the value of x i.e. 12

System.out.println("Y = "+Y);
// prints value of y i.e. 22
}

Answer 2

Hi kumaresan ,

Question is:
int X=10;
int Y=X++ + ++X;

Result is:
X=12
Y=22

Why???

🔼According to: prefix and postfix in java
( https://www.sololearn.com/learn/Java/2141/ ) :

1⃣ At first step: X++

The value of "X" (x=10) assigned to "Y" and now "Y" is 10,
Then, the value of "X" incremented to 11 and now, "X" is 11.

2⃣ Second step: ++X

At this point, at first, the value of "X" incremented to 12 and Final value of "X" is 12 and then 12 added to "Y" (Y=10),so:

X=12
Y=10+12=22

Ok?
Goodluck 😉 🙋