Unexpected Output of array in c++

Question

in this statement the is expected to be 0 but it's 8!(like my code named "arr").why?
int b[6] = {12, 35, 212, 17, 9};

cout<< b[6] << endl;

Answer 1

The memory you are trying to access is out of the bounds of the array. You haven't assigned a value to it, so you get whatever was stored in that memory cell before, which is not necessarily 0.

Answer 2

Mohsen you have defined an array b of size 6 and are trying to access the 7th element which does not exist. Remember that array indexes start from 0. The value of 8 that you get may be from a random area of memory. This type of out of bounds access can also generate an error.

Answer 3

thanks Naitomea & Sonic.
but when does it store 8 value so it accidently use it?!

Answer 4

array indexes starts from 0 , and you are not storing anything at 6th position , that's why